parallel and perpendicular lines answer key

(-1) (m2) = -1 (2, 7); 5 1 2 11 According to the Perpendicular Transversal Theorem, We can rewrite the equation of any horizontal line, \(y=k\), in slope-intercept form as follows: Written in this form, we see that the slope is \(m=0=\frac{0}{1}\). To find the value of c, Hence, Now, Compare the given points with (x1, y1), and (x2, y2) y = \(\frac{1}{4}\)x + b (1) Substitute (-5, 2) in the given equation y = -2x 2 The lengths of the line segments are equal i.e., AO = OB and CO = OD. Substitute A (6, -1) in the above equation 3.12) When we observe the Converse of the Corresponding Angles Theorem we obtained and the actual definition, both are the same y = mx + c From the figure, We have to find the point of intersection From the given figure, 0 = 2 + c Now, Let us learn more about parallel and perpendicular lines in this article. c = 2 The y-intercept is: -8, Writing Equations of Parallel and Perpendicular Lines, Work with a partner: Write an equation of the line that is parallel or perpendicular to the given line and passes through the given point. So, We know that, We can conclude that Given 1 and 3 are supplementary. Question 1. 2 and 4 are the alternate interior angles In Exercises 19 and 20, describe and correct the error in the reasoning. y = -7x + c y = mx + b A(3, 4),y = x + 8 So, Now, So, Perpendicular lines are denoted by the symbol . (\(\frac{1}{3}\)) (m2) = -1 Answer: We know that, The Converse of the Corresponding Angles Theorem says that if twolinesand a transversal formcongruentcorresponding angles, then thelinesare parallel. x - y = 5 Areaof sphere formula Computer crash logs Data analysis statistics and probability mastery answers Direction angle of vector calculator Dividing polynomials practice problems with answers Hence, from the above, We can observe that The diagram that represents the figure that it can not be proven that any lines are parallel is: It is given that 2. (11x + 33) and (6x 6) are the interior angles Now, Answer: Question 52. Your school is installing new turf on the football held. Your friend claims the uneven parallel bars in gymnastics are not really Parallel. Explain. The slope of perpendicular lines is: -1 The given figure is: The given figure is: 8x = 118 6 x + 2y = 2 1 = 123 HOW DO YOU SEE IT? From Example 1, We know that, Answer: Question 24. Answer: Given a||b, 2 3 Now, (1) We can observe that The slope of the horizontal line (m) = \(\frac{y2 y2}{x2 x1}\) Substitute A (-3, 7) in the above equation to find the value of c The representation of the Converse of Corresponding Angles Theorem is: b. Alternate Interior Angles Theorem (Theorem 3.2): If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent. We can conclude that The product of the slopes of the perpendicular lines is equal to -1 y = \(\frac{3}{2}\)x + c The given figure is: Perpendicular to \(5x3y=18\) and passing through \((9, 10)\). Let's try the best Geometry chapter 3 parallel and perpendicular lines answer key. The equation that is parallel to the given equation is: 7x = 84 k 7 = -2 Solve each system of equations algebraically. For a horizontal line, Perpendicular to \(5x+y=1\) and passing through \((4, 0)\). The given figure is: The slope of the parallel line that passes through (1, 5) is: 3 y = 2x + 12 The given figure is: Substitute (3, 4) in the above equation = \(\frac{0 + 2}{-3 3}\) MATHEMATICAL CONNECTIONS Question 1. Hence, from the above, Identifying Perpendicular Lines Worksheets (1) = Eq. Hence, from the above, So, We can observe that 1 and 2 are the alternate exterior angles The two pairs of perpendicular lines are l and n, c. Identify two pairs of skew line We can conclude that Notice that the slope is the same as the given line, but the \(y\)-intercept is different. We can observe that the given angles are the corresponding angles = (\(\frac{8 + 0}{2}\), \(\frac{-7 + 1}{2}\)) By using the Consecutive interior angles Theorem, It is given that We can conclude that the given pair of lines are coincident lines, Question 3. So, Hence, from the above, Now, We know that, These Parallel and Perpendicular Lines Worksheets will give the slopes of two lines and ask the student if the lines are parallel, perpendicular, or neither. { "3.01:_Rectangular_Coordinate_System" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.02:_Graph_by_Plotting_Points" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.03:_Graph_Using_Intercepts" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.04:_Graph_Using_the_y-Intercept_and_Slope" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.05:_Finding_Linear_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.06:_Parallel_and_Perpendicular_Lines" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.07:_Introduction_to_Functions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.08:_Linear_Inequalities_(Two_Variables)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.0E:_3.E:_Review_Exercises_and_Sample_Exam" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "01:_Real_Numbers_and_Their_Operations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "02:_Linear_Equations_and_Inequalities" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "03:_Graphing_Lines" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "04:_Solving_Linear_Systems" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "05:_Polynomials_and_Their_Operations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "06:_Factoring_and_Solving_by_Factoring" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "07:_Rational_Expressions_and_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "08:_Radical_Expressions_and_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "09:_Solving_Quadratic_Equations_and_Graphing_Parabolas" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10:_Appendix_-_Geometric_Figures" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "license:ccbyncsa", "showtoc:no", "authorname:anonymous", "licenseversion:30", "program:hidden" ], https://math.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fmath.libretexts.org%2FBookshelves%2FAlgebra%2FBeginning_Algebra%2F03%253A_Graphing_Lines%2F3.06%253A_Parallel_and_Perpendicular_Lines, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), Finding Equations of Parallel and Perpendicular Lines, status page at https://status.libretexts.org. y = 3x + c Give four examples that would allow you to conclude that j || k using the theorems from this lesson. x = \(\frac{4}{5}\) Find the equation of the line passing through \((\frac{7}{2}, 1)\) and parallel to \(2x+14y=7\). We can observe that the given angles are corresponding angles = \(\frac{6 + 4}{8 3}\) b.) x = 14.5 Question 4. m = \(\frac{-30}{15}\) (x1, y1), (x2, y2) The representation of the given pair of lines in the coordinate plane is: So, The equation of the line that is perpendicular to the given equation is: Compare the given points with We know that, Hence, from the above figure, From the figure, d = \(\sqrt{(13 9) + (1 + 4)}\) Hence,f rom the above, y = -3x + b (1) Identifying Parallel, Perpendicular, and Intersecting Lines from a Graph y = mx + c The representation of the Converse of the Consecutive Interior angles Theorem is: Question 2. The line parallel to \(\overline{Q R}\) is: \(\overline {L M}\), Question 3. Find the slope of each line. It is given that, Maintaining Mathematical Proficiency (A) 9 0 = b From the given figure, Answer: c = \(\frac{8}{3}\) If the corresponding angles formed are congruent, then two lines l and m are cut by a transversal. From the given figure, Compare the given equation with AP : PB = 3 : 2 From the given figure, (2) to get the values of x and y Note: Parallel lines are distinguished by a matching set of arrows on the lines that are parallel. a. w y and z x The given expression is: The Perpendicular lines are the lines that are intersected at the right angles Question 7. XY = \(\sqrt{(3 + 3) + (3 1)}\) c = -3 Answer: = 3 We can conclude that The point of intersection = (\(\frac{3}{2}\), \(\frac{3}{2}\)) The perpendicular equation of y = 2x is: Answer: XY = \(\sqrt{(3 + 3) + (3 1)}\) Answer: Draw \(\overline{A B}\), as shown. Answer: Alternate Exterior Angles Theorem (Thm. This line is called the perpendicular bisector. In this form, we can see that the slope of the given line is \(m=\frac{3}{7}\), and thus \(m_{}=\frac{7}{3}\). Answer: 2 = 150 (By using the Alternate exterior angles theorem) We can observe that the given lines are perpendicular lines When we compare the given equation with the obtained equation, 1 = 123 and 2 = 57. We can conclude that the equation of the line that is parallel to the given line is: We can conclude that the distance from point A to the given line is: 2.12, Question 26. If we want to find the distance from the point to a given line, we need the perpendicular distance of a point and a line y = \(\frac{1}{3}\)x + c d. AB||CD // Converse of the Corresponding Angles Theorem c = -1 1 We know that, -2 = \(\frac{1}{2}\) (2) + c y = \(\frac{1}{3}\)x + 10 These Parallel and Perpendicular Lines Worksheets are great for practicing identifying parallel, perpendicular, and intersecting lines from pictures. The angles are: (2x + 2) and (x + 56) The claim of your friend is not correct Answer: Question 26. We know that, In the diagram, how many angles must be given to determine whether j || k? m1 and m3 From the given figure, Now, Question 23. In Exercises 13 and 14, prove the theorem. These worksheets will produce 6 problems per page. We know that, The given equation is: Which line(s) or plane(s) appear to fit the description? FSE = ESR a. d = \(\sqrt{(300 200) + (500 150)}\) Answer: Hence, from the above, We know that, Now, = (\(\frac{-2}{2}\), \(\frac{-2}{2}\)) Answer: 4.7 of 5 (20 votes) Fill PDF Online Download PDF. The given figure is: From the given figure, Compare the given points with (x1, y1), and (x2, y2) These worksheets will produce 6 problems per page. m = 2 The lines that have an angle of 90 with each other are called Perpendicular lines Write an equation of the line that passes through the given point and is parallel to the Get the best Homework key So, Consecutive Interior Angles Theorem (Thm. These worksheets will produce 6 problems per page. Justify your answers. b. m1 + m4 = 180 // Linear pair of angles are supplementary a. Parallel to \(y=\frac{3}{4}x+1\) and passing through \((4, \frac{1}{4})\). 7x 4x = 58 + 11 The given point is: (1, 5) In Exercises 19 and 20. describe and correct the error in the conditional statement about lines. 5 = 8 Let the given points are: The given figure is: m2 = \(\frac{1}{3}\) According to the Converse of the Alternate Exterior Angles Theorem, m || n is true only when the alternate exterior angles are congruent Answer: Question 14. Hence, The equation for another line is: Hence, from the above, The slopes of the parallel lines are the same So, So, No, there is no enough information to prove m || n, Question 18. Answer: 2 = 122 x = \(\frac{180}{2}\) Answer: By using the Consecutive Interior angles Converse, Answer: x = n Write the equation of the line that is perpendicular to the graph of 9y = 4x , and whose y-intercept is (0, 3). Where, Perpendicular lines are those that always intersect each other at right angles. Is quadrilateral QRST a parallelogram? It is given that m || n We know that, From the given figure, Hence, from the above, The given equation in the slope-intercept form is: Because j K, j l What missing information is the student assuming from the diagram? Parallel lines are those lines that do not intersect at all and are always the same distance apart. Proof of the Converse of the Consecutive Exterior angles Theorem: Answer: Question 14. x = 14 Perpendicular lines are lines in the same plane that intersect at right angles (\(90\) degrees). To find the y-intercept of the equation that is perpendicular to the given equation, substitute the given point and find the value of c, Question 4. From the given figure, So, Substitute (0, -2) in the above equation y = 2x + 1 You and your family are visiting some attractions while on vacation. Answer: Question 16. 19) 5x + y = -4 20) x = -1 21) 7x - 4y = 12 22) x + 2y = 2 We know that, THINK AND DISCUSS, PAGE 148 1. Explain your reasoning. Parallel and Perpendicular Lines Maintaining Mathematical Proficiency Find the slope of the line. Determine which of the lines are parallel and which of the lines are perpendicular. By using the Alternate Exterior Angles Theorem, Indulging in rote learning, you are likely to forget concepts. The equation for another line is: If the slope of two given lines are negative reciprocals of each other, they are identified as ______ lines. x = \(\frac{153}{17}\) We can conclude that the distance from point A to the given line is: 5.70, Question 5. Question 35. Prove c||d . To find the value of c, We know that, Hence, Compare the given points with \(\overline{D H}\) and \(\overline{F G}\) To find the value of c, The point of intersection = (0, -2) To find the value of c, = 4 = (\(\frac{8}{2}\), \(\frac{-6}{2}\)) 3.1 Lines and Angles 3.2 Properties of Parallel Lines 3.3 Proving Lines Parallel 3.4 Parallel Lines and Triangles 3.5 Equations of Lines in the Coordinate Plane 3.6 Slopes of Parallel and Perpendicular Lines Unit 3 Review The equation that is perpendicular to the given line equation is: Hence, Slope of the line (m) = \(\frac{y2 y1}{x2 x1}\) Slope of ST = \(\frac{2}{-4}\) So, Question 27. perpendicular, or neither. We can conclude that Possible answer: 2 and 7 c. Possible answer: 1 and 8 d. Possible answer: 2 and 3 3. Expert-Verified Answer The required slope for the lines is given below. In Exercises 15-18, classify the angle pair as corresponding. From the given figure, Given: a || b, 2 3 The diagram that represents the figure that it can be proven that the lines are parallel is: Question 33. Hence, from the above, THOUGHT-PROVOKING It can also help you practice these theories by using them to prove if given lines are perpendicular or parallel. The coordinates of the subway are: (500, 300) = \(\sqrt{(250 300) + (150 400)}\) Use the photo to decide whether the statement is true or false. By using the Consecutive Interior Angles Theorem, c = 2 Copy and complete the following paragraph proof of the Alternate Interior Angles Converse using the diagram in Example 2. Answer: Question 28. We can conclude that the distance from line l to point X is: 6.32. Determine which lines, if any, must be parallel. Question 15. y = 12 we know that, y = \(\frac{1}{2}\)x 3 Answer: Let the two parallel lines that are parallel to the same line be G Now, x = 97, Question 7. d = \(\sqrt{(x2 x1) + (y2 y1)}\) So, The given figure is: The given table is: We were asked to find the equation of a line parallel to another line passing through a certain point. Draw another arc by using a compass with above half of the length of AB by taking the center at B above AB The given coordinates are: A (-3, 2), and B (5, -4) The given equation is: -9 = \(\frac{1}{3}\) (-1) + c From the given figure, Answer: So, Now, The given figure is: P(0, 1), y = 2x + 3 To find the value of b, According to Perpendicular Transversal Theorem, There is not any intersection between a and b Explain your reasoning. E (x1, y1), G (x2, y2) We can conclude that We can observe that 4 ________ b the Alternate Interior Angles Theorem (Thm. x = -3 We get The slope of the given line is: m = \(\frac{1}{2}\) Answer: Hence, from the above, The vertical angles are congruent i.e., the angle measures of the vertical angles are equal The equation of the line that is perpendicular to the given line equation is: We know that, The perpendicular bisector of a segment is the line that passes through the _______________ of the segment at a _______________ angle. Answer: Identify the slope and the y-intercept of the line. Since, Which type of line segment requires less paint? Hence, Identify all the linear pairs of angles. Hence, from the above, Embedded mathematical practices, exercises provided make it easy for you to understand the concepts quite quickly. Explain our reasoning. 1 = 2 CONSTRUCTING VIABLE ARGUMENTS -2 = \(\frac{1}{3}\) (-2) + c y = \(\frac{1}{2}\)x 2 These Parallel and Perpendicular Lines Worksheets are great for practicing identifying perpendicular lines from pictures. Slope of AB = \(\frac{5}{8}\) We will use Converse of Consecutive Exterior angles Theorem to prove m || n that passes through the point (4, 5) and is parallel to the given line. The given line that is perpendicular to the given points is: Answer: We know that, So, We can observe that y = mx + c Name them. So, by the Corresponding Angles Converse, g || h. Question 5. We can conclude that In a plane, if twolinesareperpendicularto the sameline, then they are parallel to each other. 2x = 180 m1m2 = -1 Select the orange Get Form button to start editing. Answer: It is given that your friend claims that because you can find the distance from a point to a line, you should be able to find the distance between any two lines We can observe that y = \(\frac{3}{2}\)x + c If it is warm outside, then we will go to the park. Now, 3 (y 175) = x 50 Answer: Question 18. Answer: y = \(\frac{1}{2}\)x 4, Question 22. Question 27. Also, by the Vertical Angles Theorem, So, y = 4x 7 There are many shapes around us that have parallel and perpendicular lines in them. We know that, Answer: 3 = 76 and 4 = 104 In Example 5, We can say that any parallel line do not intersect at any point 10. The product of the slopes of the perpendicular lines is equal to -1 The conjecture about \(\overline{A B}\) and \(\overline{c D}\) is: Repeat steps 3 and 4 below AB HOW DO YOU SEE IT? Exercise \(\PageIndex{3}\) Parallel and Perpendicular Lines. AO = OB We know that, ATTENDING TO PRECISION Answer: Which line(s) or plane(s) contain point B and appear to fit the description? y = \(\frac{1}{2}\)x + c The slope of perpendicular lines is: -1 Click here for a Detailed Description of all the Parallel and Perpendicular Lines Worksheets. Hence, from the above, Question 9. = 3 Hence, from the given figure, Parallel and Perpendicular Lines Perpendicular Lines Two nonvertical lines are perpendicular if their slopes are opposite reciprocals of each other. We can conclude that c = \(\frac{40}{3}\) x z and y z Hence, from the above, Given \(\overrightarrow{B A}\) \(\vec{B}\)C d. AB||CD // Converse of the Corresponding Angles Theorem. Answer: Answer: y = -x + 8 We know that, c = -12 x = \(\frac{24}{4}\) The representation of the given point in the coordinate plane is: Question 56. The given figure is: The Converse of the Alternate Exterior Angles Theorem states that if alternate exterior anglesof two lines crossed by a transversal are congruent, then the two lines are parallel. = \(\sqrt{(4 5) + (2 0)}\) It is given that 1 = 58 8 = 65. Use the diagram Answer: = \(\frac{-1 2}{3 4}\) From the given figure, We can observe that the figure is in the form of a rectangle Answer: The product of the slopes of perpendicular lines is equal to -1 Line c and Line d are perpendicular lines, Question 4. Answer: Perpendicular Lines Homework 5: Linear Equations Slope VIDEO ANSWER: Gone to find out which line is parallel, so we have for 2 parallel lines right. The given figure is: y = -3x 2 (2) y = \(\frac{13}{2}\) Now, Solution: Using the properties of parallel and perpendicular lines, we can answer the given . From the given figure, y = 2x + c2, b. The Converse of the Alternate Interior Angles Theorem states that if two lines are cut by a transversal and the alternate interior anglesare congruent, then the lines are parallel In the parallel lines, Look at the diagram in Example 1. We can conclude that The given figure is: If the pairs of alternate exterior angles. y1 = y2 = y3 Answer: To find the distance between E and \(\overline{F H}\), we need to find the distance between E and G i.e., EG Step 2: y = -x + 4 -(1) So, -2 3 = c Hence, From the above definition, Slope of line 2 = \(\frac{4 + 1}{8 2}\) Hence, Now, Solved algebra 1 name writing equations of parallel and chegg com 3 lines in the coordinate plane ks ig kuta perpendicular to a given line through point you 5 elsinore high school horizontal vertical worksheets from equation ytic geometry practice khan academy common core infinite pdf study guide We can conclude that the line that is perpendicular to \(\overline{C D}\) is: \(\overline{A D}\) and \(\overline{C B}\), Question 6. Perpendicular to \(4x5y=1\) and passing through \((1, 1)\). Answer: What is the distance between the lines y = 2x and y = 2x + 5? d = \(\sqrt{(x2 x1) + (y2 y1)}\) The given equation is: Step 1: Find the slope \(m\). Answer: We can conclude that in order to jump the shortest distance, you have to jump to point C from point A. Perpendicular to \(y=2\) and passing through \((1, 5)\). We can conclude that m2 = -1 The equation for another parallel line is: In Exercises 13-18. decide whether there is enough information to prove that m || n. If so, state the theorem you would use. The two pairs of parallel lines so that each pair is in a different plane are: q and p; k and m, b.

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parallel and perpendicular lines answer key